-16x^2+2336x=52864

Solution for -16x^2+2336x=52864 equation:

-16x^2+2336x=52864

We move all terms to the left:

-16x^2+2336x-(52864)=0

a = -16; b = 2336; c = -52864;
Δ = b2-4ac
Δ = 23362-4·(-16)·(-52864)
Δ = 2073600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2073600}=1440$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2336)-1440}{2*-16}=\frac{-3776}{-32}
=+118
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2336)+1440}{2*-16}=\frac{-896}{-32}
=+28
$